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If (a + b) tan (theta - phi) = (a-b) tan...

`If (a + b) tan (theta - phi) = (a-b) tan (theta + phi) " and " a cos 2 phi + b cos 2 theta = c, "show that" a^(2) -b^(2) + c^(2) = 2a cos 2 phi`

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The correct Answer is:
`a^(2) - b^(2) + c^(2) = 2ca cos 2phi`
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