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sin alpha + sin beta = a "and" cos alpha...

`sin alpha + sin beta = a "and" cos alpha + cos beta = b`
`cos (alpha + beta) =`

A

`(a^(2)-b^(2))/(a^(2)+b^(2))`

B

`-(a^(2) - b^(2))/(a^(2) + b^(2))`

C

`(a^(2) + b^(2))/(a^(2) - b^(2))`

D

`-(a^(2) + b^(2))/(a^(2) - b^(2))`

Text Solution

Verified by Experts

The correct Answer is:
B
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