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sin alpha + sin beta = a "and" cos alpha...

`sin alpha + sin beta = a "and" cos alpha + cos beta = b`
`(tan alpha + tan beta)/(1-tan alpha tan beta)=`

A

`(a^(2) + b^(2))/(2ab)`

B

`(b^(2)-a^(2))/(2ab)`

C

`(2ab)/(b^(2) + a^(2))`

D

`(2ab)/(b^(2) - a^(2))`

Text Solution

Verified by Experts

The correct Answer is:
D
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