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If ninN then ^(n)C0+^(n+1)C1+^(n+2)C2+.....

If n`in`N then `^(n)C_0+^(n+1)C_1+^(n+2)C_2+....+^(n+r)C_r` is equal to

A

`.^(m+n)C_(n)`

B

`.^(m+n)C_(n-1)`

C

`.^(m)C_(1)+^(m+1)C_(2)+^(m+2)C_(3)+....+^(m+n-1)C_(n)`

D

`.^(m+n)C_(m)`

Text Solution

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The correct Answer is:
A, B, D
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