The function f(x)=(1-sinx)/((pi-2x)^(2))...

The function f(x)`=(1-sinx)/((pi-2x)^(2))` is underfined at `x=(pi)/(2)`.Redefine the function f(x) so as to make it continuous at `x=(pi)/(2)`.

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The correct Answer is:

`f(x)={{:((1-sin x)/((pi-2pi)^(2))"," "when"" x ne (pi)/(2)),((1)/(8)","," when " x=(pi)/(2)):}`

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