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If p^(2)=a^(2)cos^(2)theta+b^(2)sin^(2)t...

If `p^(2)=a^(2)cos^(2)theta+b^(2)sin^(2)theta`, show that, `p+(d^(2)p)/(d theta^(2))=(a^(2)b^(2))/(p^(3))`.

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