The pressure p and the volume v of a gas are connected by the equation `pv^(1.4)=k`, where k is a constant. Prove that a decrease of `0.5%` in the volume of the gas corresponds to an increase of `0.7%` in the pressure.

The pressure p and the volume v of a gas are connected by the relation pv^(1.4)=k , where k is a constant. Then a decrease of 0.5 % in the volume of the gas corresponds to an increase of pressure by-

The pressure p, volume V and temperature T for a certain gas are related by p = (AT - BT^(2))/V , where A and B are constants. The work done by the gas when the temperature changes from T_(1) to T_(2) while the pressure remains constant, is given by

Why is the pressure of a given amount of gas increased when the temperature of the gas is raised at constant volume?

Why does the volume of a given mass of gas increase on decreasing its pressure at constant temperature?

A certain amount of an ideal gas is enclosed in a cylinder fitted with a movable piston. What would be the changes of the volume of the gas in the following processes? (i) The pressure of the gas is reduced by 25% at constant temperature. (ii) The temperature of the gas is increased by 50% constant pressure.

At 2 atm pressure and 0^(@) temperature volume of a gas of mass is 500cc. Keeping pressure constant if the temperature has been rised to 273^(@) C, what will be the volume of the gas?