If the line ax+by+c=0 is a normal to the curve xy=1 at the point (1,1), then prove that a and b are of opposite signs.

If the line ax+by+c=0 is a normal to the curve xy=1 then

If line ax+by+c=0 is normal to the curve xy+5=0 then a and b are of :

If the line ax+by+c=0,abne0 , is a tangent to the curve xy=1-2x , then

If the line a x+b y+c=0 is a normal to the curve x y=1, then (a) a >0,b >0 (b) a >0,b >0 (d) a 0

The normal to the curve x^2+2xy-3y^2=0 at (1,1) :

The normal to the curve, x^(2)+2xy-3y^(2)=0 at (1, 1)-

The equation of the normal to the curve y=e^(-2|x| at the point where the curve cuts the line x=-1/2 , is

The point on the curve xy^(2)=1 that is nearest to the origin is-

The normal at the point (1,1) on the curve 2y + x^(2) = 3 is

Find the normal to the curve x=a(1+cos theta),y=a sintheta at theta. Prove that it always passes through a fixed point and find that fixed point.