What normal to the curve `y=x^(2)` forms the shortest chord ?

Verified by Experts

The correct Answer is:

`y+-(1)/(sqrt(2))x+1`

Similar Questions

Explore conceptually related problems

The normals to the curve y=x^2+1 , drawn at the points with the abscissa x_1=0,x_2=-1" and " x_3=(5)/(2)

The distance between the origin and the normal to the curve y=e^(2x)+x^2 at the point x = 0

The equation of the normal to the curve y=e^(-2|x| at the point where the curve cuts the line x=-1/2 , is

The normal to the curve x^(2) = 4y passing (1,2) is

The slope of the normal to the curve y = 2x^(2) + 3 sin x at x = 0 is

If x+4y=14 is a normal to the curve y^2=ax^3 -beta at (2,3) then value of alpha+beta is

Find the equation of the normal to the curve x^(2) = 4y which passes through the point (1, 2).

The equation of the normal to the curve x^(3)+y^(3)=8xy at the point where it meets the parabola y^(2)=4x is -

Find the equations of tangent and normal to the curve y(x-2)(x-3)-x+7=0 at the point where it meets the x-axis.

Find the equation of the normal to the curve x^3+y^3=8x y at the point where it meets the curve y^2=4x other than the origin.