(1+1/(2!)+1/(4!)+1/(6!).....oo)/(1+1/(3!...

`(1+1/(2!)+1/(4!)+1/(6!).....oo)/(1+1/(3!)+1/(5!)+1/(7!)+....oo)` equals

A

`(e^2+1)/(e^2-1)`

B

`(e^2-1)/(e^2+1)`

C

`e^2+1`

D

`e^2-1`

Verified by Experts

The correct Answer is:

A

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