A function ` f : R to R ` is defined by ` f(x) =x^(2)` .Then show that f is neither nor surfection .

Let f:R rarr R defined by f(x)= x^2/(1+x^2) . Prove that f is neither injective nor surjective.

If f : R to R is defined by f (x) =x ^(2) - 3x + 2, find f (f (x)).

If the function f: R to R is defined by f(x) =(x^(2)+1)^(35) for all x in RR then f is

If the function f: R to R is defined by f(x)=x^(2)-6x-14 , then f^(-1)(2) is equal to -

Let the function f : R to R be defined by f(x)= 2x + cos x , then f(x)-

A function f:R to R is defined by f(x)=(x-1)(x-2) . Which one of the following is correct in respect of the function?

The function f:R to R is defined by f(x)=cos^(2)x+sin^(4)x for x in R . Then the range of f(x) is

Let the function f:R to R be defined by f(x)=x+sinx for all x in R. Then f is -

Draw the graph of the function f: R to R defined by f(x)=x^(3), x in R .

Fill in the blanks : If a function f : R to R is defined by f(x) = 2x+3 then f^(-1) (19)="____" (R is the set real numbers ).