If ` alpha = 3 sin ^(-1) ""((6)/(11) )and beta =3 cos ^(-1)""((4)/(9))`, where the inverse trigonometric function take only the priencipal values , then the correct option (s) is are -
A
`cos beta gt 0 `
B
`sin beta lt 0`
C
`cos ( alpha + beta ) gt 0`
D
`cos alpha lt 0 `
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