The length of each side of an equilateral triangle increases at the rate of 2cm/sec. Find the rate of increase of the area of the triangle, when the length of each sides is 10cm.

The radius of a circle is increasing at a rate of 2.5 cm/sec. Find the rate of increase of the area of the circle when its radius is 5cm.

If the side of an equilateral triangle increases at the rate of sqrt(3) cm/s and its area at the rate of 12 cm^(2) /s, find the side of the triangle .

The sides of an equilateral triangle are increasing at the rate of 2 cm//s ., then the rate at which the area (in cm^(2)//s ) increases when the side is 10 cm , is-

The rate of increase of a side of a square is 1 cm/sec. The rate of increase of area of the square, when length of a side of the square is 2 cm, is

If the rate of increasae of the side of a squre is 1 cm/sec , the rate of increase of the area of the square when its side 2 cm, is

Draw a equilateral triangle with length of side 6 cm .

The radius of a circle is increasing uniformly at the rate of 3 cm/s. Find the rate at which the area of the circle is increasing when the radius is 10 cm.

If the length of the sides of an equilateral triangle be increased by 1 cm each, then the area of the triangle increases by sqrt(3) sq-cm. Find the length of the equilateral triangle.