The solution of the diferential equation...

The solution of the diferential equation `(y^(2)+2x)(dy)/(dx)=y` satisfies `x=1,y=1`. Then the solution is -

A

`x=y^(2)(1+log_(e)y)`

B

`y=x^(2)(1+log_(e)x)`

C

`x=y^(2)(1-log_(e)y)`

D

`y=x^(2)(1-log_(e)x)`

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