The area (in square units) bounded by th...

The area (in square units) bounded by the curves `y=sqrt(x),2y-x+3=0`, x -axis and lying in the first quadrant is -

A

9

B

36

C

18

D

`(27)/(4)`

Verified by Experts

Similar Questions

Explore conceptually related problems

The area (in square unit) bounded by the curve f(x)=4-|x| and the x-axis is -

The area (in square unit ) bounded by the curves y= |x| - 1 and y= -|x| +1 is-

Area ( in square unit ) bounded by the curve y= sqrt(x) , the straight line x=2y+3 in first quadrant and x- axis is-

The area (in square unit) bounded by the curve y= sec x, the x-axis and the lines x=0 and x=(pi)/(4) is-

The area (in square unit ) bounded by the curve -3y^(2) = x-9 and the lines x=0, y=0 and y=1 is-

The area (in square unit) of the region bounded by the curves y=x^(3) and y=2x^(2) is-

The area (in square unit) bounded by the curve y= sin x, x-axis and the two ordinates x = pi ,x =2pi is-

The area of the region, bounded by the curves y=sin^(-1)x+x(1-x) and y=sin^(-1)x-x(1-x) in the first quadrant is-

The area (in squnit) bounded by the curve y= sinx , x-axis and the two ordintes x= pi,x=2pi is

The area (in square unit) of the region bounded by the curve y=|x-2| , x-axis and the ordinates x=1, x=3 is -