Home
Class 12
MATHS
The locus of the foot of perpendicular d...

The locus of the foot of perpendicular drawn from the centre of the ellipse `x^(2)+3y^(2)=6` on any tangent to it is-

A

`(x^(2)-y^(2))^(2)=6x^(2)+2y^(2)`

B

`(x^(2)-y^(2))^(2)=6x^(2)-2y^(2)`

C

`(x^(2)+y^(2))^(2)=6x^(2)+2y^(2)`

D

`(x^(2)+y^(2))^(2)=6x^(2)-2y^(2)`

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

The locus of the foot of the perpendicular from the center of the hyperbola x y=1 on a variable tangent is

Find the locus of the foot of the perpendicular drawn from the center upon any tangent to the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1.

Find the foot of perpendicular drawn from the point (2, 2) to the line 3x - 4y + 5 = 0

If F_1 and F_2 are the feet of the perpendiculars from the foci S_1a n dS_2 of the ellipse (x^2)/(25)+(y^2)/(16)=1 on the tangent at any point P on the ellipse, then prove that S_1F_1+S_2F_2geq8.

The locus of foot of the perpendiculars drawn from the vertex on a variable tangent to the parabola y^2 = 4ax is

The locus of the foot of perpendicular from my focus of a hyperbola upon any tangent to the hyperbola is the auxiliary circle of the hyperbola. Consider the foci of a hyperbola as (-3, -2) and (5,6) and the foot of perpendicular from the focus (5, 6) upon a tangent to the hyperbola as (2, 5). The directrix of the hyperbola corresponding to the focus (5, 6) is

The locus of the foot of perpendicular from my focus of a hyperbola upon any tangent to the hyperbola is the auxiliary circle of the hyperbola. Consider the foci of a hyperbola as (-3, -2) and (5,6) and the foot of perpendicular from the focus (5, 6) upon a tangent to the hyperbola as (2, 5). The conjugate axis of the hyperbola is

The coordinates of the foot of the perpendicular drawn from the point P(x,y,z) upon the zx- plane are-

Find the locus of the foot of the perpendicular drawn from the origin to the straight line which passes through the fixed point (a,b).

A circle of radius r passes through the origin and intersects the x-axis and y-axis at P and Q respectively. Show that the equation to the locus of the foot of the perpendicular drawn form the origin upon the line segment bar (PQ) is (x^(2)+y^(2))^(3)=4r^(2)x^(2)y^(2) .