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f(x)=(1)/(x)["log"(1+bx)-"log"(1-ax)] is...

`f(x)=(1)/(x)["log"(1+bx)-"log"(1-ax)]` is not defined at x=0 . What value is to be assigned to f (0) so that f (x) will be continuous at x=0?

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The correct Answer is:
Therefore , the required assigned value of f (0) is (a+b).
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