Home
Class 12
MATHS
IF x^3-2x^2y^2+5x+y-5=0 and y(1)=1, then...

IF `x^3-2x^2y^2+5x+y-5=0` and y(1)=1, then -

A

`y'(1)=4/3`

B

`y''(1)=(-4)/3`

C

`y''(1)=-8 22/27`

D

`y'(1)=2/3`

Text Solution

Verified by Experts

The correct Answer is:
A, C
Promotional Banner

Topper's Solved these Questions

  • SECOND ORDER DERIVATIVE

    CHHAYA PUBLICATION|Exercise Sample Question for Competitive Examination (Integer answer type)|5 Videos
  • SECOND ORDER DERIVATIVE

    CHHAYA PUBLICATION|Exercise Sample Question for Competitive Examination (Matrix Match Type)|2 Videos
  • SECOND ORDER DERIVATIVE

    CHHAYA PUBLICATION|Exercise Long answer type Question|22 Videos
  • REVISION OF PREVIOUS TWO DIMENSIONAL COORDINATE GEOMETRY

    CHHAYA PUBLICATION|Exercise Sample Questions for Competitive Exams E (Assertion - Reason Type )|2 Videos
  • SEQUENCE AND SERIES

    CHHAYA PUBLICATION|Exercise Sample Questions for Competitive Exams (Assertion-Reason Type)|2 Videos

Similar Questions

Explore conceptually related problems

The line tangent to the curves y^3-x^2y+5y-2x=0 and x^2-x^3y^2+5x+2y=0 at the origin intersect at an angle theta equal to (a) pi/6 (b) pi/4 (c) pi/3 (d) pi/2

If the circles x^2+y^2+2a x+c y+a=0 and x^2+y^2-3a x+d y-1=0 intersects at points P and Q , then find the values of a for which the line 5x+b y-a=0 passes through Pa n dQdot

A circle through the common points of the circles x^2+y^2-x+7y-3=0 and x^2+y^2-5x+y+1=0 has its centre on the line x+y=0.Find the equations of the circle.

For hyperbola whose center is at (1, 2) and the asymptotes are parallel to lines 2x+3y=0 and x+2y=1 , the equation of the hyperbola passing through (2, 4) is (a) (2x+3y-5)(x+2y-8)=40 (b) (2x+3y-8)(x+2y-5)=40 (c) (2x+3y-8)(x+2y-5)=30 (d) none of these

If the foci of a hyperbola lie on y=x and one of the asymptotes is y=2x , then the equation of the hyperbola, given that it passes through (3, 4), is (a) x^2-y^2-5/2x y+5=0 (b) 2x^2-2y^2+5x y+5=0 (c) 2x^2+2y^2-5x y+10=0 (d) none of these

Find the equation of the circle passing through the points of intersection of the circles x^(2) + y^(2) - x + 7y - 3 = 0, x^(2) + y^(2) - 5x - y + 1 = 0 and having its centre on the line x+y = 0.

If (x_1-x_2)^2+(y_1-y_2)^2=a^2 , (x_2-x_3)^2+(y_2-y_3)^2=b^2 , (x_3-x_1)^2+(y_3-y_1)^2=c^2 , and 2s=a+b+c then what willl be the value of 1/4|[x_1,y_1, 1],[x_2,y_2, 1],[x_3,y_3, 1]|^2

If x^2+y^2=x^2y^2 then find the range of (5x+12 y+7x y)/(x y) .

Find the image of the circle x^2+y^2-2x+4y-4=0 in the line 2x-3y+5=0