Home
Class 12
MATHS
If 0lexle2pi, the function f(x) = sinx i...

If `0lexle2pi`, the function f(x) = sinx is minimum at -

A

`x=(3pi)/(2)`

B

`x=pi`

C

`x=(3pi)/(4)`

D

`x=2pi`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • MAXIMA AND MINIMA

    CHHAYA PUBLICATION|Exercise EXERCISE Very Short Answer Type Questions|20 Videos

  • MAXIMA AND MINIMA

    CHHAYA PUBLICATION|Exercise EXERCISE Short Answer Type Questions|42 Videos

  • MAXIMA AND MINIMA

    CHHAYA PUBLICATION|Exercise Sample Questions for Competitive Examination E|2 Videos

  • MATHEMATICAL REASONING

    CHHAYA PUBLICATION|Exercise JEE Main (AIEEE) Archive (2016 )|1 Videos

  • MCQ ZONE

    CHHAYA PUBLICATION|Exercise Question Paper 7|80 Videos

Similar Questions

Explore conceptually related problems

Verify Rolle's theorem for function f(x) = 4^(sinx) in the interval [0,pi] .

Show that the function f(x)=|sinx+cosx| is continuous at x = pi .

The function f(x) =(1-sinx)/((pi-2x)^(2)) is underfined at x=(pi)/(2) .Redefine the function f(x) so as to make it continuous at x=(pi)/(2) .

Draw the graph of the function f(x)=m a x{sinx ,cos2x},x in [0,2pi] . Write the equivalent definition of f(x) and find the range of the function.

Verify Rolle's theorem for the function f(x)=4^(sinx) in the interval [0,pi] .

The function f(x)=(sinx)/(sinx-cosx) is discontinuous at -

Prove that the function f given by f(x) = log sin x is increasing on (0,(pi)/(2)) and decreasing on ((pi)/(2),pi) .

For what values of x is the function f(x)=(sinx)/(cosx-sinx) not defined ?

Show that , the function log cos^(2)x+secx is maximum at x=0 and minimum at x=(pi)/(3) .

Find the absolute maximum and minimum values of the function f given by f(x) = cos^(2)x+sinx, x in [ 0,pi]