A particle moves in a straight line such that its distance x from a fixed point on it at any time t is given by `x=(1)/(4)t^(4)-2t^(3)+4t^(2)-7` Find the time when its velocity is maximum and the time when its acceleration is minimum .

Answer

The velocity is maximum at time `t=2 - (2sqrt(3))/(3)` units and the acceleration is minimum at time t=2 units.