Home
Class 12
MATHS
In R, consider the planes P(1): y = 0 an...

In R, consider the planes `P_(1): y = 0 and P_(2) : x +z = 1`. Let `P_(3)` be a plane, different from `P_(1) and P_(2)`, which passes through the intersection of `P_(1) and P_(2)`. If the distance of the point (0, 1,1) from `P_(3)` is 1 and the distance of a point `(alpha, beta, gamma) " from " P_(3)` is 2, then which of the following relations is (are) true?

A

`2alpha + beta + 2gamma + 2 = 0`

B

`2 alpha + beta - 2gamma - 10 = 0`

C

`2alpha - beta + 2gamma - 8 = 0`

D

`2alpha - beta + 2gamma + 4 = 0`

Text Solution

Verified by Experts

The correct Answer is:
A, B, D
Promotional Banner

Topper's Solved these Questions

  • ARCHIVE

    CHHAYA PUBLICATION|Exercise JEE Main (AIEEE) Archive|6 Videos

  • ALGEBRA

    CHHAYA PUBLICATION|Exercise JEE ADVANCED ARCHIVE 2016|5 Videos

  • BINARY OPERATION

    CHHAYA PUBLICATION|Exercise Assertion-Reason Type|2 Videos

Similar Questions

Explore conceptually related problems

In R^(3) , consider the planes P_(1):y=0 and P_(2),x+z=1. Let P_(3) be a plane, different from P_(1) and P_(2) which passes through the intersection of P_(1) and P_(2) , If the distance of the point (0,1,0) from P_(3) is 1 and the distance of a point (alpha,beta,gamma) from P_(3) is 2, then which of the following relation(s) is/are true? (a) 2alpha + beta + 2gamma +2 = 0 (b) 2alpha -beta + 2gamma +4=0 (c) 2alpha + beta - 2gamma- 10 =0 (d) 2alpha- beta+ 2gamma-8=0

A ray of light passing through the point (1,2) is reflected on the x-axis at a point P and passes through the point (5,3) , then the abscissa of the point P is-

What is the length of the focal distance from the point P(x_(1),y_(1)) on the parabola y^(2) =4ax ?

Find the coordinates of the foot of the perpendicular and the prependicular distance of the point P(3,2,1) from the plane 2x-y+z+1=0 . Find also the image of the poitn in the plane.

A variable line passes through a fixed point P. The algebraic sum of the perpendiculars drawn from the points (2,0), (0,2) and (1,1) on the line is zero. Find the coordinate of the point P.

Vertices of a parallelogram taken in order are A( 2,-1,4)B(1,0,-1)C( 1,2,3) and D. Distance of the point P ( 8, 2,-12) from the plane of the parallelogram is

The points (p+1,1), (2p+1,3) and (2p+2, 2p) are collinear, if

Find the equation of the plane passing through the point A(1,2,1) and perpendicular to the line joining the points P(1,4,2) and Q (2,3,5) . Also , find the distance of this plane from the line (x+3)/(2)=(y-5)/(-1)=(z-7)/(-1) .

A line through point A(1,3) and parallel to the line x-y+1 = 0 meets the line 2x-3y + 9 = 0 at point P. Find distance AP without finding point P.

A point P(x,y) moves in the xy - plane in such a way that its distance from the point (0,4) is equal to (2)/(3) rd of its distance from the x axis , find the equation to the locus of P.