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Let n(1) "and" n(2) be the number of red...

Let `n_(1) "and" n_(2)` be the number of red and black balls, respectively, in box I. Let `n_(3) "and" n_(4)` be the number of red black balls, respectively in box II.
One of the two boxes, box 1 and box II was selected at random and a ball was found to be rad. if the probability that this red ball was drawn from box II is `1/3` then the correct option (s) with the possible values of correct option (s) with the possible values of correct option (s) with the possible values of `n_(1),n_(2),n_(3) "and"n_(4) "is (are)"`

A

`n_(1) = 3, n_(2) = 3, n_(3) = 5, n_(4) = 15`

B

`n_(1) = 3, n_(2) = 6,n_(3) = 10, n_(4) = 50`

C

`n_(1) = 8,n_(2) = 6, n_(3) = 5, n_(4) = 20`

D

`n_(1) = 6,n_(2) = 12, n_(3) = 5, n_(4) = 20`

Text Solution

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The correct Answer is:
A, B, C, D
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