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Let n(1) "and" n(2) be the number of red...

Let `n_(1) "and" n_(2)` be the number of red and black balls, respectively, in box I. Let `n_(3) "and" n_(4)` be the number of red black balls, respectively in box II.
A ball is drawn at random from box 1 and transferred to box II. If the probability of drawing a red ball from box 1, after this transfer, is `1/3` then the correct option (s) with the possible values of `n_(1) "and" n_(2)` is (are)-

A

`n_(1) = 4 "and" n_(2) = 6`

B

`n_(1) = 2 "and" n_(2) = 3`

C

`n_(1) = 10 "and" n_(2) = 20`

D

`n_(1) = 3 "and" n_(2) = 6`

Text Solution

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The correct Answer is:
A, B, C
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