If P(A-B)=(1)/(3), P(A)=(1)/(2) and P(B)...

If `P(A-B)=(1)/(3), P(A)=(1)/(2) and P(B)=(1)/(3)`, calculate the probability that out of the two events A and B, only B will occur.

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The correct Answer is:

the probability that only B occurs `=P(B-A)=(1)/(6)`

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