If `barA and barB` are the events complementary to the events A and B respectively, prove that,
`P(barA or barB)=1-P(A)P(B//A)`.

If bar(A) and bar(B) are the events complementary to the events A and B respectively, prove that, P(bar(A) or bar(B)) = 1 - P(A cap B).

If E and F are the complementary events of events E and F , respectively, and if P(F) in [0,1]

If the events A and B are equally likely, then P(A) =

If events A and B are complementary to each other, then P(B) =?

If the events A and B are not mutually exclusive then P(A cup B) =

For any two events A and B prove that, P(A cup B) le P(A) + P(B)

For any two events A and B prove that, P(A//B) lt P(B//A) " if " P(A) lt P(B)

If A and B are two events such that P(A)>0a n d P(B)!=1, t h e nP( barA / barB ) is equal to ( Here barAa n d barB are complements of Aa n dB , respectively .) a. 1-P(A/B) b. 1-P(( barA )/B) c. (1-P(AuuB))/(P( barB )) d. (P( barA ))/(P(B))

For any two events A and b prove that, P(A) ge P(A cap B) ge P(A) + P(B) - 1

Foe any two events A and B prove that , P(A)geP(AcapB)geP(A)+P(B)-1