A and B play alternately with an unbiased die. He who first throws a 'six' wins. If A begins, show that his chance of winning is `(6)/(11)`.

A and B play alternately with a pair of unbiased dice. A wins if he throws 6 before B throws 7 and B wins if he throws 7 before A throws 6. If A begins, show that his chance of winning is (30)/(61) .

Two players A and B toss a die alternately he who first throws a six wins the game if A begins what is the probability that he wins? What is the probability of B winning the game?

A and B alternatively toss a fair coin. The first once to throw a head wins. If A starts find their respective probabilities of winning.

A and B alternatively toss a fair coin. The first one to throw a head wins. If A starts, find their respective probabilities of winning.

A, B and C in order toss an unbiased coin. The first who throws 'head' wins. Find the respective probabilities of winning.

A and B play for a prize of Rs 99 the prize is to be won by a player who first throes a '3' with one die A first throes and if he fails B throws and if he fails A again throws and so on find their respective expectations

A gambler rolls two unbiased dice and stands to loss Rs 2 if he fails to throw a six to win Rs 4 if he throws one six and to win Rs 10 if he throws two sixes is the game fair ?

A and B toss a coin alternately untill one of them gets a head for the first time and wins the toss. If A begin, find the respective probability ties for A and B to win the toss.

A and B throw a die alternatively till one of them gets a '6' and wins the game. Find their respective probabilities of winning, if A starts first.

Forty team play a tournament. Each team plays every other team just once. Each game results in a win for one team. If each team has a 50% chance of winning each game, the probability that the end of the tournament, every team has won a different number of games is a. 1//780 b. 40 !//2^(780) c. 40 !//2^(780) d. none of these