Show that for two non-mutually exclusive events A and B,
`P(A cup B)=P(A) +P(B)-P(A cap B)`

For any two events A and B, show that, P(A uu B) = P(A) + P(B) - P(A nn B) .

If A and B are two mutually exclusive event then P(A-B) =

For two mutually exclusive events A and B, P(A)=(1)/(2) and P(A cup B)=(2)/(3) , then the value of P(B) will be

If A and B are two mutually exclusive events and P(A cup B) ne 0 , then show that, P[A//(A cup B)] =(P(A))/(P(A)+P(B)) .

For two mutually exclusive events A and B, P(A) + P(B) equals to 1. The above statement is

For any two events A and B prove that, P(A cup B) le P(A) + P(B)

For two mutually exclusive events A and B,P(A)=1/2and P(AcupB)=2/3 ,then the value of P(B) will be

If the events A and B are not mutually exclusive then P(A cup B) =

For any two events A and B prove that P(A cup B) le P{A) + P (B) .

If A and B are mutually exclusive events, show that P(A/(A uu B)) = frac(P(A))(P(A)+P(B))