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If E(1) ,E(2),E(3)…E(n) be n independent...

If `E_(1) ,E_(2),E_(3)…E_(n)` be n independent events such that `P(Ei)=(1)/(1+i)` for `1 le I le n` then the chance that none of `E_(1),E_(2),E_(3) … E_(n)` occur is

A

`1/(n+1)`

B

`(n!)/((n+1)!)`

C

`n/(n+1)`

D

`(2n)/(n+1)`

Text Solution

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The correct Answer is:
A, B
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