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Given: NH(3)(g)+3Cl(2)(g)toNCl(3) (g)+3H...

Given: `NH_(3)(g)+3Cl_(2)(g)toNCl_(3) (g)+3HCl(g),-DeltaH_(1)`
`N_(2)(g)+3H_(2)(g)to2NH_(3)(g),DeltaH_(2)`
`H_(2)(g)+Cl_(2)(g)to2HCl(g),DeltaH_(3)`
Heat of formation `(DeltaH_(f)) ` of `NCl_(3)` in terms of `DeltaH_(1), DeltaH_(2) and DeltaH_(3)` is-

A

`-DeltaH_(1)+(DeltaH_(2))/(2)-(3)/(2)DeltaH_(3)`

B

`DeltaH_(1)+(DeltaH_(2))/(2)-(3)/(2)DeltaH_(3)`

C

`DeltaH_(1)-(DeltaH_(2))/(2)-(3)/(2)DeltaH_(3)`

D

none of these

Text Solution

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The correct Answer is:
A
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