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At 25^(@)C , the heat of combustion of n...

At `25^(@)C` , the heat of combustion of naphthalene at constant volume is `-1230 " kcal mol"^(-1)`. Calculate the heat of reaction at constant pressure and `25^(@)C`.

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`C_(10)H_(8)(s)+12O_(2)(g) to 10 CO_(2)(g)+4H_(2)O(g)`
For the above reaction, `Delta n= (10+4)-12=2`
`Delta H= Delta U+ Delta nRT`
`= (-1230+2xx1.987xx298xx10^(-3))` kcal
`= -1228.81` kcal
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