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Find Delta S^(0) of the reaction : CH(...

Find `Delta S^(0)` of the reaction :
`CH_(4)(g)+CO_(2)(g) to 2CO(g)+2H_(2)(g)`
Given : `S^(0)(CH_(4))=188 " J mol"^(-1) K^(-1)`,
`S^(0)(CO_(2))= 213.8 " J mol"^(-1). K^(-1)`,
`S^(0)(CO)= 197.6 " J mol"^(-1). K^(-1)`
`S^(0)(H_(2))= 130.7 " J mol"^(-1). K^(-1)`

Text Solution

Verified by Experts

`DeltaS^(0)= 2S^(0)(CO)+2S^(0)(H_(2))-S^(0)(CH_(4))-S^(0)(CO_(2))`
`=(2xx 197.6+2xx130.7-188-213.8) J. K^(-1) " mol"^(-1)`
`= 254.8 J. K^(-1)`
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