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Why does BF3 forms an adduct with ammon...

Why does `BF_3` forms an adduct with ammonia?

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In `NH_3` molecule N-atom has a lone p air of electrons and in `BF_3` molecule 2 electrons are requir e d to complete the octet of B-atom . Thus, `NH_3` (a Lewis base) react s with `BF_3` (a Lewis acid) to form an adduct.
`H_3N : +BF_3 to [H_3N to BF_3]`
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