Amongst the following, the one which can exist in free state as a stable compound is-

Options

A. `C_(7)H_(9)O`
B. `C_(8)H_(12)O`
C. `C_(6)H_(11)O`
D. `C_(10)H_(17)O_(2)`

Answer

B

Explanation

Double Bond Equivalent of a compound is given by, `DEB = (sum(v-2))/(2)+1`, where n = number of atoms of a particular type present in the molecule, v = valency of each atom present in the molecule.
DEB values for the given compounds area as follow:
`C_(7)H_(9)O:(7(4-2)+9(1-2)+1(2-2))/(2)+3.5`
`C_(8)H_(12)O:(8(4-2)+12(1-2)+1(2-2))/(2)+1=3`
`C_(10)H_(17)O_(2):(10(4-2)+17(1-2)+2(2-2))/(2)+1=2.5`
Compound with fractional DEB values are unstable in free state.