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In a mixture, two enantiomers are found ...

In a mixture, two enantiomers are found to be present in the amount of 85% and 15% respectively. The enantiomeric excess (e.e) is-

A

0.85

B

0.15

C

0.7

D

0.6

Text Solution

Verified by Experts

The correct Answer is:
C
Enantiomeric excess = (85 - 15) % = 70%.
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