0.495 g of an organic compound on combustion gave 0.99 g of `CO_(2) and 0.405` g of water. Calculate the percentages of carbon and hydrogen in the compound.

Explanation

Amount of C in the compound `=(12)/(44)x0.99=0.27`
Amount of H in the compound `=(2)/(18)xx0.405=0.045`
`therefore % "of C in the compound"=(12)/(44)xx0.99xx(100)/(0.495)=54.54`
`therefore "of H in the compound" =(2)/(18)xx0.405xx(100)/(0.495)=9.09`