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0.05 g of an organic compound when anal...

0.05 g of an organic compound when analysed by Dumas method produced 62.0 mL of nitrogen at STP. Determine the percentages of nitrogen in the compound.

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Mass of 62.0 mL (STP) of `N_(2)=(28xx620)/(22400)`
`%"of N in the compound" = (28xx62.0)/(22400)xx(100)/(0.05)=155`
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