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Identify the products obtained when ethy...

Identify the products obtained when ethylene gas is passed through bromine -water in the presence of sodium chloride.

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`CH_(2) = CH_(2) underset(NaCl)overset(Br_(2)//H_(2)O)rarr underset(underset(Br)(|))(C)H_(2) - underset(underset(Br)(|))(C)H_(2) + underset(underset(OH)(|))(C)H_(2) - underset(underset(Br)(|))(C)H_(2) + underset(underset(Cl)(|))(C)H_(2)- underset(underset(Br)(|))(C)H_(2)`
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CHHAYA PUBLICATION-HYDROCARBONS-HIGHER ORDER THINKING SKILL (HOTS) QUESTIONS
  1. Unlike acetylene, ethylene dissolves in concentrated sulphuric acid- w...

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  2. Write the structure of the product expected to be formed when CH2=CH-o...

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  3. Identify the products obtained when ethylene gas is passed through bro...

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  4. Which alkenes are formed on dehydrating the following alcohols in pres...

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  5. Which alkenes are formed on dehydrating the following alcohols in pres...

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  6. The conjugated dienes are more reactive than alkenes which in turn are...

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  7. Calculate the resonance energy of 1,3-butadiene from the following dat...

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  8. Dehydration of alcohols to alkene is carried out by treating with conc...

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  9. How will you prepare ethylbenzene be using ethyne as the only organic ...

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  10. Explain bromination of benzene requires FeBr3 as catalyst, while brom...

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  11. Neither vinyl chloride (CH2=CH-Cl) nor chlorobenzene (C6H5-Cl) can be ...

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  12. Two methods for the preparation of propylbenzene are given below- ...

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  13. Which ring (A to B) in each of the following compounds will undergo ni...

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  14. Which ring (A to B) in each of the following compounds will undergo ni...

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  15. Which ring (A to B) in each of the following compounds will undergo ni...

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  16. Which ring (A to B) in each of the following compounds will undergo ni...

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  17. Write the names and structures of the compounds formed during Friede...

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  18. Write the names and structures of the compounds formed during Friede...

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  19. Write the names and structures of the compounds formed during Friede...

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  20. Show the formation of the electrophile in each case: Cl2//AlCl3

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