2.7 gram of a metal after reaction with excess acid produces 3.36 litre of `H_(2)` at NTP . What is the equivalent weight of the metal ?

1.25 gm of a metal process 62.4 ml H_2 at NTP, Calculate the equivalent. weight of the metal.

If 10 C of electricity is passed through an aqueous solution of a metal salt , 2.08xx10^(19) atoms are produced at the cathode . Find the equivalent weight of the metal , if its atomic weight is 27 .

P_(4)+3NaOH+3H_(2)OtoPH_(3)+3NaH_(2)PO_(2) What is the equivalent weight of P_(4) in the reaction ?

3.26g of zinc reacts with acid to liberated 1.12 L of hydrogen gas (H_(2)) at STP. Calculate the relative equivalent weight of zinc.

A metal M forms the sulphate M_2(SO_4)_3 0.596 gm of the sample reacts with excess BaCl_2 to give, 1.22 gm BaSO_4 . What is the atomic weight of the M ? (S = 32, Ba + 137.3)

The same amount of electricity is passed through acidified water and an aqueous solution of a metal chloride . As a result 7.4L H_(2) , gas at STP in the first case and 21 g metal in the second case are produced . Calculate the equivalent weight of the metal ? If the specific heat of the metal is 0.094 , then find the atomic weight of the metal ?

0.3 g of a metal reacts with dilute acid and produce 110 mL of H_(2) which is collected above water at 17^(@)C temperature and 755 mm Hg pressure. Find equivalent mass of the metal. [pressure of water vapour at 17^(@)C=14.4mmHg ].

P_(4) + 3 NaOH + 3 H_(2) O to PH_(3) + 3 NaH_(2) PO_(2) What is the equivalent weight of P_(4) in the above reaction ?