Home
Class 12
CHEMISTRY
The main oxides formed on combustion of...

The main oxides formed on combustion of Li, Na and K in excess of air are respectively -

A

`Li_(2)O , Na_(2) O_(2) ` and `KO_(2)`

B

`Li_(2) O , Na_(2)O ` and `KO_(2)`

C

`LiO_(2) , Na_(2)O_(2)` and `K_(2)O`

D

`Li_(2) O_(2) , Na_(2) O_(2)` and `KO_(2)`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • PREVIOUS YEAR QUESTION PAPER 2016

    CHHAYA PUBLICATION|Exercise NEET 2016 [ Phase- I]|13 Videos

  • PREVIOUS YEAR QUESTION PAPER 2016

    CHHAYA PUBLICATION|Exercise NEET 2016 [ Phase- II]|16 Videos

  • PREVIOUS YEAR QUESTION PAPER 2016

    CHHAYA PUBLICATION|Exercise WBCHSE 2016 SECTION II ( GROUP D)|8 Videos

  • PREVIOUS YEAR QUESTION PAPER 2019

    CHHAYA PUBLICATION|Exercise WBJEE 2019|18 Videos

  • PREVIOUS YEAR QUESTION PAPER 2017

    CHHAYA PUBLICATION|Exercise NEET 2017|13 Videos

Similar Questions

Explore conceptually related problems

The main oxides formed on combustion of Li, Na and K in excess of air respectively are -

Na and Li are placed in dry air. We get:

The ratio of heats liberated at 298K from the combustion of one kg of coke and byburning water gas obtained from 1kg of coke Is (Assume coke to be 100% carbon). (Given : enthalpies of combustion of CO_2, CO and H_2 are 393.5 kJ, 285 kJ, 285 kJ respectively all at 298K)

Which of the following oxides is formed when potassium metal is burnt in excess air ?

This question has Statement I and Statement II. Of the four choices given after the Statements, choose the one that best describes the two Statements. Statement -1: All alkali metals do not form superoxides as one of the main products in excess of air on heating. Statement - II: Superoxide reacts with carbon monoxide producing a white powder and liberating dioxygen.

Electromagnetic waves propagate through free space or a medium as transverse waves. The electric and magnetic fields are perpendicular to each other as well as perpendicular to the direction of propagation of waves at each point. In the direction of wave propagation, electric field vecE and magnetic field vecB form a right-handed cartesian coordinate system. During the propagation of electromagnetic wave, total energy of electromagnetic wave is distributed equally between electric and magnetic fields. Since in_0 and mu_0 are permittivity and permeability of free space, the velocity of electromagnetic wave, c=(in_0 mu_0)^(-1//2) . Energy density i.e., energy in unit volume due to electric field at any point, u_E=1/2in_0E^2 Similarly, energy density due to magnetic field , u_M=1/(2mu_0)B^2 . If the electromagnetic wave propagates along x-direction, then the equations of electric and magnetic field are respectively. E=E_0sin(omegat-kx) and B=B_0sin(omegat-kx) Here, the frequency and the wavelength of oscillating electric and magnetic fields are f=omega/(2pi) and lambda=(2pi)/k respectively. Thus E_"rms"=E_0/sqrt2 and B_"rms"=B_0/sqrt2 , where E_0/B_0=c . Therefore, average energy density baru_E=1/2in_0E_"rms"^2 and baru_M=1/(2mu_0)B_"rms"^2 . The intensity of the electromagnetic wave at a point, I=cbaru=c(baru_E+baru_B) . To answer the following questions , we assume that in case of propagation of electromagnetic wave through free space, c=3xx10^8 m.s^(-1) and mu_0=4pixx10^(-7) H.m^(-1) Relation between omega and k