Home
Class 12
CHEMISTRY
1 gram of a carbonate (M(2) CO(3)) on tr...

1 gram of a carbonate `(M_(2) CO_(3))` on treatment with excess HCl produces `0.01186` mole of `CO_(2)` . The molar mass of `M_(2) CO_(3)` in `g * mol^(-1)` is -

A

`118.6 `

B

`11.86`

C

`1186`

D

`84.3`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • PREVIOUS YEAR QUESTION PAPER 2017

    CHHAYA PUBLICATION|Exercise NEET 2017|13 Videos

  • PREVIOUS YEAR QUESTION PAPER 2017

    CHHAYA PUBLICATION|Exercise WBCHSE 2017 (SECTION II)|48 Videos

  • PREVIOUS YEAR QUESTION PAPER 2016

    CHHAYA PUBLICATION|Exercise NEET 2016 [ Phase- II]|16 Videos

  • PREVIOUS YEARS QUESTION PAPER 2016

    CHHAYA PUBLICATION|Exercise NEET 2016 (PHASE-II)|21 Videos

Similar Questions

Explore conceptually related problems

1 gram of a carbonate (M_(2)CO_(3)) on treatment with excess HCl produces 0.01186 mol of CO_(2) . The molar mass of M_(2)CO_(3) in g*mol^(-1) is-

Calculate the molar mass: (1) H_(2)O (2) CO_(2)

Excess of CO_(2) in the plant will

In excess, CO_(2)

How many gram of CaCO_3 will react with exces of dilute HCl to produce 66 gm of CO_2 ? (Ca = 40, C = 12, O = 16)

How many gram of carbon is to be burnt to produce 33g of CO_(2) ?

How many oxygen atoms are there in 1 mole of CO_(2) ?

The volume of CO_(2) formed when a mixture of 2 mol NaHCO_(3) and 1 mol Na_(2)CO_(3) at STP, is-

Calculate : (i) mass, (ii) volume at STP, (iii) number of molecules present in 0.5 mol of CO_(2) .

5 moles of Ba(OH)_2 are treated with excess of CO_2 How much BaCO_3 will be formed ?