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The ratio of mass percent of C and H of ...

The ratio of mass percent of C and H of an organic compound `(C_(X) H_(Y) O_(Z))` is 6 : 1 . If one molecule of the above compound `(C_(X) H_(Y) O_(Z))` contains half as much oxygen as required to burn one molecule of compound ` C_(X) H_(Y)` completely to `CO_(2)` and `H_(2)O` . The empirical formula of compound `C_(X) H_(Y) O_(Z)` is -

A

`C_(3)H_(4) O_(2)`

B

`C_(2) H_(4) O_(3)`

C

`C_(3) H_(6) O_(3)`

D

`C_(2) H_(4) O`

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