At STP if latent heat of fusion of ice is `6 kJ * mol^(-1)` , then find out the entropy change of fusion of ice .

Explanation

At STP , the latent heat of fusion of ice `(Delta H_("fus")) = 6 kJ * mol^(-1) = 6000 J * mol^(-1)`
We know that , the entropy change of fusion `Delta S_("fus") = (Delta H_("fus"))/( T_(f))`
`T_(f) = 0^(@) C = 273 k`
`therefore` the entropy change of fusion of ice , `Delta S _("fus") = (6000)/( 273) J * mol^(-1) * K^(-1) = 21.98 J * mol^(-1) * K^(-1)`