The rate constant of a first order reaction is `1.5xx10^(-6)s^(-1)` at a specific temperature . What percent of initial concentration of the reactant gets converted into product after 10h?

Explanation

The rate constant of a first order reaction,
`k=(2.303)/(t)log.(a)/(a-x)`
Given, `k=1.5xx10^(-6)s^(-1)andt=10xx3600=3.6xx10^(4)s`
`therefore1.5xx10^(-6)=(2.303)/(3.6xx10^(4))log.(a)/(a-x)or, log.(a)/(a-x)=0.0234`
or, `(a)/(a-x)=1.055" or, "x=(0.055a)/(1.055)=0.0521a`
`therefore " After 10hr", (0.521a)/(a)xx100=5.21%` of the initial concentration of the reactant gets converted into product.