If the concentration of the reactant of a first order reaction is `10^(-1)"mol .L"^(-1)` , the reaction -rate is `3xx10^(-4)"mol.L"^(-1).s^(-1)` . When the concentration is `10^(-2)"mol.L"^(-1)` , what is the rate of reaction ?

Explanation

For a first order reaction , rate = k [reactant]
`thereforek=("rate")/(["reactant"])=(3xx10^(-4)"mol.L"^(-1).s^(-1))/(10^(-1)"mol.L"^(-1))=3xx10^(-3)s^(-1)`
Rate constant of the reaction `=3xx10^(-3)s^(-1)`
If the concentration of the reactant `10^(-2)"mol".L^(-1)`
`thereforer=k["reactant"]=(3xx10^(-3)s^(-1))xx(10^(-2)"mol.L"^(-1)) `
`= 3xx10^(-5)"mol.L"^(-1).s^(-1)`