For the reaction `A+2Brarr3C` , the rate in terms of change in concentration of A, B and C are x, y and z `"mol .L "^(-1).s^(-1)` , respectively, Establish a relation between x , y and z .

Explanation

`-(d[A])/(dt)=-(1)/(2)(d[B])/(dt)=(1)/(3)(d[C])/(dt)`
Rate with respect to A = `-(d[A])/(dt)= " x mol . L"^(-1).s^(-1)`
Rate with respect to B = `-(d[B])/(dt)= " y mol . L"^(-1).s^(-1)`
Again , `-(d[B])/(dt)=2xx(-(d[A])/(dt))`
`therefore y = 2x " " ....[1]`
Similarly , `(d[C])/(dt)=2xx(-(d[A])/(dt))`
`therefore z = 3x [because (d[C])/(dt)=z]" "...... [2]`
Form equations [1] and [2] we get , `x=(y)/(2)=(z)/(3)`