For the reaction : `aA+bBrarrcC` , the rate law is , `r=k[A]^(m)[B]^(n)` . If the initial concentration of A and B are doubled, then find the ratio of the new initial rate to the original initial rate.

Explanation

`r_(1) = k [A]^(m)[B]^(n)`
If the concentration of both A and B are doubled, the reaction-rate , `r_(2) = k [2A]^(m)[2B]^(n)=2^(m)xx2^(n)k[A]^(m)[B]^(n)`
`thereforer_(2) = 2^(m+n)xxk[A]^(m)[B]^(n) " or, "r_(2)=2^(m+n)xxr_(1)`
or, `(r_(2))/(r_(1))=2^(m+n)`