The reaction `aArarrbB` is a zero order in A , with a rate constant of k. show that the rate formation of B is `bxxk`.

Explanation

The rate of the reaction `=-(1)/(a)(d[A])/(dt)=(1)/(b)(d[B])/(dt)=k[A]^(0)=k `
`therefore` The rate of formation of `B,(d[B])/(dt)=bxxk`