How does the initial concentration of the reactant in a first order reaction very with time ?

The initial concentration of the reactant is a first order reaction is a. What will be its concentration after 4^(th) half-life ?

If the t 1/2 for any reaction be inversely proportion at to the initial Concentration of the reactant then the order of reaction is—

The initial concentration of the reactant in a first order reaction is a . It takes time t for the completion of noth fraction of the reaction. Will it take time 2t for the completion of the same fraction if the initial concentration of the reactant is made twice ?

What will be the nature of the graph showing the concentration of the reactant and time of a first order reaction ?

The half-life of a reaction is halved as the initial concentration of the reactant is doubled. The order of reaction is:

The initial concentration of the reactant in a zero order reaction is 1.386 "mol.L"^(-1) The half-life of the reaction is 20s. Calculate: the concentration of the reactant after 30s from the initiation of the reaction.

The initial concentration of the reactant in a zero order reaction is 1.386 "mol.L"^(-1) The half-life of the reaction is 20s. Calculate: the rate constant

When the initial concentration of the reactant in a reaction id doubled, the half -life of the reaction becomes double . Determine the order of the reaction.

For a reaction RrarrP , half-life (t_(1//2)) is observed to be independent of the initial concentration of reactants. What is the order of the reaction ?