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For an elementary reaction A+BrarrC, the...

For an elementary reaction `A+BrarrC,` the rate constant increase 10 times on increasing the temperature form `27^(@)` By 10 degrees. Find out the activation energy of the reaction.

Text Solution

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For calculating activation energy `(E_(a))` of a reaction where rate constants at two different temperatures are given , we use the relation `log.(k_(2))/(k_(1))=(E_(a))/(2.303R)((T_(2)-T_(1))/(T_(1)T_(2)))`
Given: `k_(2)=10k_(1),T_(1)=300K and T_(2)=310K`.
Substituting these values into the above equation gives
`log10=(E)/(2.303R)((310-300)/(310xx300))`
or, `E_(a)=178.06"kJ.mol"^(-1)`
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