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For a chemical reaction at 27^(@)C the ...

For a chemical reaction at `27^(@)C` the activation energy is 600 R. The ratio of the rate constant at `327 ^(@)C` to that of at `27^(@)C` will be—

A

2

B

40

C

e

D

`e^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
In `(k_(327^(@)C))/(k_(27^(@)C))=(E_(a))/(R)((1)/(T_(1))-(1)/(T_(2))) ("where"T_(2)gtT_(1))`
or,In `(k_(327^(@)C))/(k_(27^(@)C))=(600R)/(R)((1)/(300)-(1)/(600))`
or,In `(k_(327^(@)C))/(k_(27^(@)C))=600((2-1)/(600))=1 " or, In " (k_(327))/(k_(27))=1`
or, or, `(k_(327^(@)C))/(k_(27^(@)C))=e`
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